25y^2+60y+36=24

Solution for 25y^2+60y+36=24 equation:

25y^2+60y+36=24

We move all terms to the left:

25y^2+60y+36-(24)=0

We add all the numbers together, and all the variables

25y^2+60y+12=0

a = 25; b = 60; c = +12;
Δ = b2-4ac
Δ = 602-4·25·12
Δ = 2400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2400}=\sqrt{400*6}=\sqrt{400}*\sqrt{6}=20\sqrt{6}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-20\sqrt{6}}{2*25}=\frac{-60-20\sqrt{6}}{50}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+20\sqrt{6}}{2*25}=\frac{-60+20\sqrt{6}}{50}
$